BACK TO POSTS

这是一篇数学公式渲染文章

本文用于验证博客在遇到不同复杂度数学公式时的渲染鲁棒性、溢出横向滚动机制及排版节奏。

01 / 基础公式 (Basic Equations)

行内公式测试:勾股定理 a2+b2=c2a^2 + b^2 = c^2,欧拉恒等式 eiπ+1=0e^{i\pi} + 1 = 0,以及质能方程 E=mc2E = mc^2。

一元二次方程求根公式:

x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

高斯积分 (Gaussian Integral):

∫−∞∞e−x2 dx=π\int_{-\infty}^{\infty} e^{-x^2} \, dx = \sqrt{\pi}

02 / 中等复杂度分析与变换 (Analysis & Transforms)

连续函数的傅里叶变换 (Fourier Transform) 及其逆变换:

f^(ξ)=∫−∞∞f(x)e−2πixξ dx,f(x)=∫−∞∞f^(ξ)e2πixξ dξ\hat{f}(\xi) = \int_{-\infty}^{\infty} f(x) e^{-2\pi i x \xi} \, dx, \quad f(x) = \int_{-\infty}^{\infty} \hat{f}(\xi) e^{2\pi i x \xi} \, d\xi

多维矩阵表达 (Matrix Representation):

A=(a11a12…a1na21a22…a2n⋮⋮⋱⋮am1am2…amn),det⁡(A)=∑σ∈Snsgn⁡(σ)∏i=1nai,σ(i)\mathbf{A} = \begin{pmatrix} a_{11} & a_{12} & \dots & a_{1n} \\ a_{21} & a_{22} & \dots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\ a_{m1} & a_{m2} & \dots & a_{mn} \end{pmatrix}, \quad \det(\mathbf{A}) = \sum_{\sigma \in S_n} \operatorname{sgn}(\sigma) \prod_{i=1}^n a_{i, \sigma(i)}

黎曼 Zeta 函数的解析延拓方程:

ζ(s)=2sπs−1sin⁡(πs2)Γ(1−s)ζ(1−s)=1Γ(s)∫0∞xs−1ex−1 dx\zeta(s) = 2^s \pi^{s-1} \sin\left(\frac{\pi s}{2}\right) \Gamma(1-s) \zeta(1-s) = \frac{1}{\Gamma(s)} \int_0^\infty \frac{x^{s-1}}{e^x - 1} \, dx

03 / 分式嵌套与连分数 (Nested Fractions)

高阶连分数 (Continued Fractions) 嵌套测试:

x=a0+b1a1+b2a2+b3a3+b4a4+b5a5+…x = a_0 + \cfrac{b_1}{a_1 + \cfrac{b_2}{a_2 + \cfrac{b_3}{a_3 + \cfrac{b_4}{a_4 + \cfrac{b_5}{a_5 + \dots}}}}}

黄金分割比的连分数展开:

ϕ=1+11+11+11+11+…\phi = 1 + \cfrac{1}{1 + \cfrac{1}{1 + \cfrac{1}{1 + \cfrac{1}{1 + \dots}}}}

04 / 经典物理与场论方程组 (Physics & Field Equations)

麦克斯韦方程组 (Maxwell’s Equations) 的微分形式与积分形式对照:

∇⋅E=ρε0∮∂VE⋅dA=Qencε0∇⋅B=0∮∂VB⋅dA=0∇×E=−∂B∂t∮∂CE⋅dl=−dΦBdt∇×B=μ0J+μ0ε0∂E∂t∮∂CB⋅dl=μ0Ienc+μ0ε0dΦEdt\begin{aligned} \nabla \cdot \mathbf{E} &= \frac{\rho}{\varepsilon_0} & \oint_{\partial V} \mathbf{E} \cdot d\mathbf{A} &= \frac{Q_{\text{enc}}}{\varepsilon_0} \\[8pt] \nabla \cdot \mathbf{B} &= 0 & \oint_{\partial V} \mathbf{B} \cdot d\mathbf{A} &= 0 \\[8pt] \nabla \times \mathbf{E} &= -\frac{\partial \mathbf{B}}{\partial t} & \oint_{\partial C} \mathbf{E} \cdot d\mathbf{l} &= -\frac{d\Phi_B}{dt} \\[8pt] \nabla \times \mathbf{B} &= \mu_0 \mathbf{J} + \mu_0 \varepsilon_0 \frac{\partial \mathbf{E}}{\partial t} \quad & \oint_{\partial C} \mathbf{B} \cdot d\mathbf{l} &= \mu_0 I_{\text{enc}} + \mu_0 \varepsilon_0 \frac{d\Phi_E}{dt} \end{aligned}

流体力学可压缩纳维-斯托克斯方程 (Compressible Navier-Stokes Equations):

∂∂t(ρu)+∇⋅(ρu⊗u)=−∇p+∇⋅[μ(∇u+(∇u)T−23(∇⋅u)I)]+ρg\frac{\partial}{\partial t} \left( \rho \mathbf{u} \right) + \nabla \cdot \left( \rho \mathbf{u} \otimes \mathbf{u} \right) = -\nabla p + \nabla \cdot \left[ \mu \left( \nabla \mathbf{u} + (\nabla \mathbf{u})^T - \frac{2}{3} (\nabla \cdot \mathbf{u}) \mathbf{I} \right) \right] + \rho \mathbf{g}

05 / 极限复杂:相对论、量子场论与分段大公式 (Extreme Complex Formulas)

爱因斯坦场方程 (Einstein Field Equations) 及其克里斯托费尔联络 (Christoffel Symbols) 张量展开:

Rμν−12Rgμν+Λgμν=8πGc4TμνR_{\mu\nu} - \frac{1}{2}R g_{\mu\nu} + \Lambda g_{\mu\nu} = \frac{8\pi G}{c^4} T_{\mu\nu} Γμνσ=12gσρ(∂gρν∂xμ+∂gμρ∂xν−∂gμν∂xρ)\Gamma^\sigma_{\mu\nu} = \frac{1}{2} g^{\sigma\rho} \left( \frac{\partial g_{\rho\nu}}{\partial x^\mu} + \frac{\partial g_{\mu\rho}}{\partial x^\nu} - \frac{\partial g_{\mu\nu}}{\partial x^\rho} \right)

量子场论标量场路径积分生成 functional (Path Integral Generating Functional in QFT):

Z[J]=∫Dϕ exp⁡{iℏ∫d4x[12ημν∂μϕ∂νϕ−12m2ϕ2−λ4!ϕ4+J(x)ϕ(x)]}\mathcal{Z}[J] = \int \mathcal{D}\phi \, \exp\left\{ \frac{i}{\hbar} \int d^4 x \left[ \frac{1}{2} \eta^{\mu\nu} \partial_\mu \phi \partial_\nu \phi - \frac{1}{2} m^2 \phi^2 - \frac{\lambda}{4!} \phi^4 + J(x)\phi(x) \right] \right\}

复杂条件分段分布概率函数 (Piecewise Probability Density Function):

P(x,y)={exp⁡(−12(1−ρ2)[(x−μx)2σx2−2ρ(x−μx)(y−μy)σxσy+(y−μy)2σy2])2πσxσy1−ρ2if x2+y2≤R2∑k=1∞λke−λk!⋅12πkσ2exp⁡(−(x−kμ)22kσ2)if x2+y2>R2P(x, y) = \begin{cases} \cfrac{\exp\left( -\dfrac{1}{2(1-\rho^2)} \left[ \dfrac{(x-\mu_x)^2}{\sigma_x^2} - \dfrac{2\rho(x-\mu_x)(y-\mu_y)}{\sigma_x \sigma_y} + \dfrac{(y-\mu_y)^2}{\sigma_y^2} \right] \right)}{2\pi \sigma_x \sigma_y \sqrt{1-\rho^2}} & \text{if } x^2 + y^2 \le R^2 \\[16pt] \displaystyle\sum_{k=1}^{\infty} \frac{\lambda^k e^{-\lambda}}{k!} \cdot \frac{1}{\sqrt{2\pi k \sigma^2}} \exp\left(-\frac{(x - k\mu)^2}{2k\sigma^2}\right) & \text{if } x^2 + y^2 > R^2 \end{cases}

06 / 混合代码与公式测试

结合代码块与公式的复合呈现:

import numpy as np

def gaussian_integral_approximation(n_samples=1_000_000):
    # \int_{-\infty}^{\infty} e^{-x^2} dx = \sqrt{\pi}
    x = np.random.uniform(-10, 10, n_samples)
    y = np.exp(-x**2)
    integral = np.mean(y) * 20
    return integral, np.sqrt(np.pi)

print(gaussian_integral_approximation())

Br0b

个人博客,记录设计系统、前端开发与实验性想法。

‹
NO MORE POSTS
›
NO MORE POSTS